Question

rationalise the denominatir 4√3+5√2/√48+√18

Answer 1

Heya ✋

Let see your answer !!!!!

4√3 + 5√2 / √48 + √18

= 4√3 + 5√2 × (√48 - √18) / (√48 + √18) (√48 - √18)

= 4√3(√48 - √18) + 5√2(√48 - √18) / (√48)^2 - (√18)^2

= 4√144 - 4√54 + 5√96 - 5√36 / 48 - 18

= 4√144 - 4√54 + 5√96 - 5√36/30

= 4√144/30 - 4√54/30 + 5√96/30 - 5√36/30

= 2√144/15 - 2√5/15 + √96/6 - √36/6

= 2√44 - 2√5/15 + √96 - √36/6

= 2 × 12 - 2√5/15 + √96 - 6/6

= 24 - 2√5/15 + √96 - 6/6

Thanks :))))

Answer 2

Heya !

Here is yr answer.....

$= > \frac{4 \sqrt{3} + 5 \sqrt{2} }{ \sqrt{48} + \sqrt{18} } \\ \\ = > \frac{4 \sqrt{3} + 5 \sqrt{2} }{ \sqrt{48} + \sqrt{18} } \times \frac{ \sqrt{48} - \sqrt{18} }{ \sqrt{48} - \sqrt{18} } \\ \\ = > \frac{4 \sqrt{144} - 4 \sqrt{54} + 5 \sqrt{96} - 5 \sqrt{36}}{48 - 18} \\ \\ = > \frac{48 - 4 \sqrt{54} + 5 \sqrt{96} - 30}{30} \\ \\ = > \frac{4(12 - \sqrt{54} ) + 5( \sqrt{96 - 6)} }{(2)(15)} \\ \\ = > \frac{12 - \sqrt{54} + \sqrt{96} - 6 }{3}$ \\ \\

Hope it hlpz...