Question

Rationalise the denominator
1/2√7 , 1/√2 + 3​

Answer 1

Answer:

Here is the answer.

Step-by-step explanation:

$\frac{1}{2 \sqrt{7} } \\ = \frac{ \sqrt{7} }{2 \sqrt{7} \times \sqrt{7} } \\ = \frac{ \sqrt{7} }{2 \times 7} \\ = \frac{ \sqrt{7} }{14}$

$\frac{1}{ \sqrt{2} + 3} \\ = \frac{ \sqrt{2} - 3}{( \sqrt{2} + 3)( \sqrt{2} - 3) } \\ = \frac{ \sqrt{2} - 3 }{ {( \sqrt{2} )}^{2} - {(3)}^{2} } \\ = \frac{ \sqrt{2} - 3 }{2 - 9} \\ = \frac{ \sqrt{2} - 3 }{ - 7} \\ = \frac{ - (3 - \sqrt{2} )}{ - 7} \\ = \frac{1}{7} (3 - \sqrt{2} )$

Answer 2

Answer:

√7/14

3-√2/7

Step-by-step explanation:

1/2√7*√7/√7

√7/14

1/√2+3*√2-3/√2-3

√2-3/2-9

√2-3/-7

now take minus sign as common

then

-(3-√2)/-7

cut off both the minus sign of numerator and denominator

then

3-√2/7