Math, asked by bladitya12345, 7 months ago

rationalise the denominator 1/√3-√2+1​

Answers

Answered by sakariariya
1

Answer:

1/√3-√2+1×√3+√2-1÷√3+√2-1

=√3+√2-1÷(√3)^2+(√2)^2+(1)^2

√3+√2-1÷3+2+1

=√3+√2-1÷6

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