rationalise the denominator 1/√3-√2+1
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1/√3-√2+1×√3+√2-1÷√3+√2-1
=√3+√2-1÷(√3)^2+(√2)^2+(1)^2
√3+√2-1÷3+2+1
=√3+√2-1÷6
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