Question

Rationalise the denominator
1/√3 + √2 - 1

Answer 1

$:\implies \frac{1}{ \sqrt{3} + \sqrt{2} } - 1 \\ \\ :\implies \frac{1}{ \sqrt{3} + \sqrt{2} } \times \frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} - \sqrt{2} } - 1 \\ \\ :\implies \frac{ \sqrt{3} - \sqrt{2} }{ {( \sqrt{3} )}^{2} - {( \sqrt{2} )}^{2} } - 1 \\ \\ :\implies \frac{ \sqrt{3} - \sqrt{2} }{3 - 2} - 1 \\ \\ :\implies \sqrt{3} - \sqrt{2} - 1$

Hope it's helpful to you

Answer 2

Answer:

We have

3

+

2

−1

1

=

3

+

2

−1

1

×

3

+

2

+1

3

+

2

+1

=

(

3

+

2

)

2

−1

3

+

2

+1

=

3+2+2

6

−1

3

+

2

+1

=

4+2

6

3

+

2

+1

×

2

6

−4

2

6

−4

=

24−16

(

3

+

2

+1)(2

6

−4)

=

8

2

2

+2

6

−4

=

4

2

+

6

−2

Wh