rationalise the denominator 1 / root 3 - root 2
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1/√3-√2
=1/√3-√2 × √3+√2/√3+√2
=√3+√2/(√3)² - (√2)²
=√3+√2/3-2
=√3+√2/1
sahasraramadugu2005:
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Answer:
given,
1/√3-√2
rationalisation,
=1/√3-√2×√3+√2/√3+√2
=√3+√2/3-2
=√3+√2/1
=√3+√2
hi
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