Question

rationalise the denominator 1/root5+root2​

Answer 1

Answer:

√5-√2/3 is the answer

1/√5+√2

1/√5+√2×√5-√2/√5-√2

√5-√2/(√5)3-day(√2)10

√5-√2/5-2

√5-√2/3

Answer 2

Rationalization is the process of removing imaginary numbers from an algebraic expression's denominator. It's the process of transferring the radical (square root or cube root) from the fraction's bottom (denominator) to the top (numerator) (numerator). To get rid of the radicals, multiply the numerator and denominator by the denominator's conjugate.

Given- the expression is$\frac{1}{\sqrt{5}+\sqrt{2} }$

Rationalise the given expression is-

$\frac{1}{\sqrt{5}+\sqrt{2} } \times\frac{\sqrt{5} -\sqrt{2} }{\sqrt{5} -\sqrt{2} } \\=\frac{\sqrt{5} -\sqrt{2} }{(\sqrt{5}-\sqrt{2} ) ^{2} } \\=\frac{\sqrt{5}-\sqrt{2} }{5-2} } \\=\frac{\sqrt{5} -\sqrt{2} }{3}$

So, the rationalise the function is$\frac{\sqrt{5} -\sqrt{2} }{3}$.