Question

Rationalise the denominator
1/
$\sqrt{2 } + \sqrt{3}$
​

Answer 1

Answer:

√3-√2

Step-by-step explanation:

I think you asked to rationalise the denominator

1 / √2+√3

Multiply and divide √2-√3

√2-√3/2-3

√2-√3 / -1

√3-√2/1 = √3-√2

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Answer 2

Answer:

The answer is $\sqrt{2} -\sqrt{3}$.

Step-by-step explanation:

$\frac{1}{ \sqrt{2} +\sqrt{3} }$   =>   $\frac{1}{ \sqrt{2} +\sqrt{3}}$×$\frac{1}{\sqrt{2} -\sqrt{3}}$  =>  $\frac{\sqrt{2}-\sqrt{3}}{(\sqrt{2})^{2} - (\sqrt{3} ^{2})}$   =>  $\frac{\sqrt{2} -\sqrt{3}}{2-3}$  =>   $\frac{\sqrt{2} - \sqrt{3} }{1}$  =>  $\sqrt{2} - \sqrt{3}$

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