Question

rationalise the denominator ​

Answer 1

Answer:

Here is your answer bro

Answer 2

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=> $\frac{√7+√2}{9+2√14}$ × $\frac{9-2√14}{9-2√14}$

=> $\frac{9(√7+√2)~-~2√14(√7+√2)}{(9)²-(2√14)²}$

=> $\frac{9√7+9√2-2√98-2√28}{81-4~×~14}$

$= > \frac{9 \sqrt{7} + 9 \sqrt{2} - 2 \sqrt{2 \times 49} - 2 \sqrt{4 \times 7} }{25}$

=> $\frac{9√7+9√2-2~×~7√2-2~×~2√7}{25}$

=> $\frac{9√7+9√2-14√2-4√7}{25}$

=> $\frac{9√7-4√7+9√2-14√2}{25}$

=> $\frac{5√7~-~5√2}{25}$

===> $\frac{√7~~-~~√2}{5}$ ☑️

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