Question

rationalise the denominator​

Answer 1

Answer:

√2/√2+√3-√5×√2-√3+√5/√2-√3+√5

=2-√3+√5/2-3-5

=2√3+√5/2-8

=2√3+√5/-6

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Answer 2

Step-by-step explanation:

root2(root2+root3+root5)/(root2+root3-root5)(root2+root3+root5)

=2+root6+root10/(root2+root3)^2-(root5)^2

=2+root6+root10/2root6

=(2+root6+root10)*root6/2root6*root6

=2root6+6+root60/2*6

=6+2root6+2root15/12

=2(3+root6+root15)/12

=3+root6+root15/6

     

         hope it helps