Question

The father’s age is six times his son’s age. Four years hence, the age of the father will be four times his son’s age. Find the present ages, in years, of the son and the father.

Answer 1

Step-by-step explanation

PLSS MARK AS BRAINLIESTT...ALSO THAN K ME ....ME ...MATE

ANSWER

Let the present age of father's be x years and present age of son's be y years.

According to the problem

x=6y

After 4 years

x+4=4(y+4)

Hence we get two equations

x=6y ......... (1)

x+4=4(y+4) ..... (2)

Simplifying eq (2)

x+4=4y+16

x−4y=12

Put x=6y in eq (2), we get

6y−4y=12

2y=12

y=6 years

and x=6y=36 years

Present age of son =6 years

and present age of father =36 years

Answer 2

Answer:

let sons age be x

fathers age  = 6x

4 yrs from now sons age = x + 4

fathers age 4 yrs from now = 4 (x + 4 )

present age can be taken out as follows

6x + 4 = 4( x + 4 )

6x + 4 = 4x + 16

2x = 12

x = 6

So, son's present age is 6 yrs

and

father's present age is 36 years

pls mark brainliest and follow me for follow back so whenever you post your queries i can answer.