Question

Rationalise the denominator:

√2+√3/√2-√3​

Answer 1

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Answer 2

Step-by-step explanation:

$= > \frac{( \sqrt{2} + \sqrt{3}) }{( \sqrt{2} - \sqrt{3} ) }$

Multiply and divide with " √2 + √3 "

$\frac{( \sqrt{2} + \sqrt{3}) }{( \sqrt{2} - \sqrt{3}) } \times \frac{( \sqrt{2} + \sqrt{3} ) }{( \sqrt{2} + \sqrt{3} )}$

=> $\frac{ (√2 + √3)² }{ (√2)² - (√3)² }$

=> $\frac{ (√2)² + (√3)² + 2*√2*√3 }{ 2 - 3 }$

=> $\frac{ 2 + 3 + 2√6 }{ -1 }$

=> $\frac{ 5 + 2√6 }{ -1 }$