Math, asked by eudo6w9di, 11 months ago

rationalise the denominator 2 upon root 5 + root 3 + 2​

Answers

Answered by harshverdhantyagi
1

Answer:

Step-by-step explanation:

2/√5+√3+2 * √5-3√2

2(√5-3√2)/ (√5)^2  -  (√3)^2      (a-b)(a+b)=a^2-b^2

2√5-6√2/5-3

2√5-6√2/2

Answered by niharika162004
1

Step-by-step explanation:

2/√5+√3+2 ×√5-√3+2/√5-√3+2

{2(√5-√3+2)}/(√5)2 -(√3+2)2

(2√5-2√3+4)/5-7

(2√5-2√3+4)/-2

-2√5/2+2√3/2-4/2

-√5+√3-2 OR -(√5-√3+2)

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