Rationalise the denominator √3-1/√3+1
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Answered by
65
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(√3 - 1 / √3+1 )* (√3-1/√3-1 )
=( 3-1-√3)/ 2
=( 2-√3) / 2
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(√3 - 1 / √3+1 )* (√3-1/√3-1 )
=( 3-1-√3)/ 2
=( 2-√3) / 2
HOPE IT HELPS U
PLZ MARK MY ANS AS BRAINLIENT
AND DONT FORGET TO FOLLOW ME
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Answered by
71
√(3) - 1/ √(3) + 1
Multiply this by √(3) - 1/√(3) - 1
[√(3) - 1/ √(3) + 1] × [√(3) - 1/√(3) - 1]
{ √(3) - 1 } ^2 / √(3)^2 - 1^2
using (a + b)(a - b) = a^2 - b^2
3 + 1 - 2√(3) / 3 - 1
using (a - b)^2 = a^2 + b^2 - 2ab
4 - 2√(3) / 2
2 ( 2 - √(3) ) / 2
Ans. 2 - √(3)
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