Question

Rationalise the denominator 3-2√2/3+2√2

Answer 1

3-2root2/3+2root3*3-2root2/3-2root2
=(3-2root2)^2/9-8
=9+8-12root2
=17-12root2

Answer 2

Answer: After rationalisation, we get that 17+12√2.

Step-by-step explanation:

Since we have given that

$\frac{3-2\sqrt{2}}{3+2\sqrt{2}}$

We need to rationalise the denominator:

So, we will multiply 3-2√2 by both the numerator and denominator.

So, it becomes,

$\dfrac{3-2\sqrt{2}\times (3-2\sqrt{2})}{(3+2\sqrt{2})\times (3-2\sqrt{2})}\\\\=\dfrac{9+8-12\sqrt{2}}{9-8}\\\\=17+12\sqrt{2}$

Hence, after rationalisation, we get that 17+12√2.