rationalise the denominator √3+√2/√3-√2
Answers
Answered by
3
☆☆
=root 3 + root 2/ root 3 -root 2
=(root 3 + root 2 )^2 / root 3^2 - root 2^2
=root 3^2 + 2×root 3 × root 2 + root 2^2/ 3-2
=3 + 2 root 6 + 2
=5+2 root 6
Answered by
0
Answer:
5 + 2√6
Step-by-step explanation:
= (√3 + √2)/ (√3 - √2)
= (√3 + √2) / (√3 - √2) × (√3 + √2)/ (√3 + √2)
= √3(√3 + √2) + √2(√3 + √2) / √3(√3 + √2) - √2(√3 + √2)
= (√9 + √6 + √6 + √4) / (√9 - √4)
= (3 + 2√6 + 2)/ (3 - 2)
= (5 + 2√6)/1
= 5 + 2√6
Similar questions