Math, asked by durgesh4992, 7 months ago

rationalise the denominator √3+√2/√3-√2 ​

Answers

Answered by Anonymous
3

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\small\green {\sf{Answer }}

=root 3 + root 2/ root 3 -root 2

=(root 3 + root 2 )^2 / root 3^2 - root 2^2

=root 3^2 + 2×root 3 × root 2 + root 2^2/ 3-2

=3 + 2 root 6 + 2

=5+2 root 6

Answered by VXS
0

Answer:

5 + 2√6

Step-by-step explanation:

= (√3 + √2)/ (√3 - √2)

= (√3 + √2) / (√3 - √2) × (√3 + √2)/ (√3 + √2)

= √3(√3 + √2) + √2(√3 + √2) / √3(√3 + √2) - √2(√3 + √2)

= (√9 + √6 + √6 + √4) / (√9 - √4)

= (3 + 2√6 + 2)/ (3 - 2)

= (5 + 2√6)/1

= 5 + 2√6

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