Question

rationalise the denominator 3-√2÷3+√2​

Answer 1

Step-by-step explanation:

Since we have given that

\dfrac{\sqrt{3}+\sqrt{2}}{\sqrt{3}-\sqrt{2}}

3

−

2

3

+

2

We need to rationalize the denominator.

As we know that while rationalize the denominator with \sqrt{3}+\sqrt{2}

3

+

2

So, it becomes,

\begin{gathered}\dfrac{\sqrt{3}+\sqrt{2}}{\sqrt{3}-\sqrt{2}}\times \dfrac{\sqrt{3}+\sqrt{2}}{\sqrt{3}+\sqrt{2}}}\\\\=\dfrac{(\sqrt{3}+\sqrt{2})^2}{3-2}\\\\=3+2+2\sqrt{6}\\\\=5+2\sqrt{6}\end{gathered}

Hence, simplified form is 5+2\sqrt{6}5+2

6

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Rationalise the denomi nator of root 6/root 3-root 2