rationalise the denominator
√3+√2/√3-√2
AbhishGS:
5+2rt(6).
Answers
Answered by
14
hey dear here is your answer
=root 3 + root 2/ root 3 -root 2
=(root 3 + root 2 )^2 / root 3^2 - root 2^2
=root 3^2 + 2×root 3 × root 2 + root 2^2/ 3-2
=3 + 2 root 6 + 2
=5+2 root 6
hope it helps you...
=root 3 + root 2/ root 3 -root 2
=(root 3 + root 2 )^2 / root 3^2 - root 2^2
=root 3^2 + 2×root 3 × root 2 + root 2^2/ 3-2
=3 + 2 root 6 + 2
=5+2 root 6
hope it helps you...
Answered by
10
Rationalized ur question we get this....
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