rationalise the denominator √3-√2÷√3+√2
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Answered by
1
Answer:
Step-by-step explanation:
√3-√2/√3+√2= (√3-√2/√3+√2) X(√3-√2/√3-√2)
= (√3-√2)² / (√3)²-(√2)²
=3+2+2 X 6 / 3-2
= 5+12/1
= 17/1
= 17
ghaimonicapc99ff:
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Answered by
3
Answer:
√3-√2/√3+√2= (√3-√2/√3+√2) X(√3-√2/√3-√2)
= (√3-√2)² / (√3)²-(√2)²
=3+2+2 X 6 / 3-2
= 5+12/1
= 17/1
= 17
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