Math, asked by iraja3876, 1 month ago

rationalise the denominator 3/5√2-2√3​

Answers

Answered by kunjvoracrvcom
0

Answer:

\frac{15\sqrt{2}+6\sqrt{3}}{38}{}

Step-by-step explanation:

\frac{3}{5\sqrt{2}-2\sqrt{3}  }\\\frac{3}{5\sqrt{2}-2\sqrt{3}}*\frac{5\sqrt{2}+2\sqrt{3}}{5\sqrt{2}+2\sqrt{3}}\\\frac{3(5\sqrt{2}+2\sqrt{3})}{(5\sqrt{2}-2\sqrt{3})(5\sqrt{2}+2\sqrt{3})}    \\\frac{15\sqrt{2}+6\sqrt{3}  }{(5\sqrt{2)} ^{2}-(2\sqrt{3)} ^{2}  } \\\frac{15\sqrt{2}+6\sqrt{3}  }{50-12}\\\frac{15\sqrt{2}+6\sqrt{3}}{38} \\

If my answer helps you than please mark my answer as brainliest

Similar questions