Question

Rationalise the denominator √3-5√2/√3+2

Answer 1

Answer:

3-2root3-5root6+10root2

Answer 2

Question:

Rationalise the denominator

$\frac{ \sqrt{3} - 5 \sqrt{2} }{ \sqrt{3} + 2}$

Solution:

$= > \frac{ \sqrt{3} - 5 \sqrt{2} }{ \sqrt{3} + 2} \times \frac{ \sqrt{3} - 2}{ \sqrt{3} - 2} \\ \\ We\: know\: that\:\\ (a+b)(a-b)=a^2-b^2\\ \\= > \frac{ \sqrt{3}( \sqrt{3} - 2) - 5 \sqrt{2} ( \sqrt{3} - 2) }{( \sqrt{3}) {}^{2} - ( {2})^{2} } \\ \\ = > \frac{ \sqrt{9} - 2 \sqrt{3} - 5 \sqrt{6} + 10\sqrt{2} }{3 - 4} \\ \\ = > \frac{3 - 2 \sqrt{3} - 5 \sqrt{6} + 10 \sqrt{2} }{ - 1}\\ \\=> \frac{\cancel{-}(-3+2 \sqrt{3}+5 \sqrt{6}-10 \sqrt{2}</p><p>}{\cancel{-1}} \\ \\ => 2 \sqrt{3}+5 \sqrt{6}-10 \sqrt{2} -3$