Question

rationalise the denominator 5/√3-√5

Answer 1

Heya !!!

Identity used :

$(x + y)(x - y) = {x}^{2} - {y}^{2}$

$\frac{5}{ \sqrt{3} - \sqrt{5} } \\ \\ = \frac{5}{ \sqrt{3} - \sqrt{5} } \times \frac{ \sqrt{3} + \sqrt{5} }{ \sqrt{3} + \sqrt{5} } \\ \\ = \frac{5( \sqrt{3} + \sqrt{5}) }{ {( \sqrt{3} )}^{2} - {( \sqrt{5}) }^{2} } \\ \\ = \frac{5 \sqrt{3} + 5 \sqrt{5} }{3 - 5} \\ \\ = \frac{5 \sqrt{3} + 5 \sqrt{5} }{ - 2} \\ \\ = \frac{ - 5 \sqrt{3} - 5 \sqrt{5} }{2}$

Hope this helps ☺

Answer 2

Heya mate !!!!!

Here's your answer =>=>

Refer to the attached file ^^^^

Hope it will help you ☆▪☆

Thanks ^_^

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