rationalise the denominator 5+4under root 3/7-4under root 3
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Heya!!!
5 + 4✓3 / 7 - 4✓3
=> 5 + 4✓3 / 7 -4✓3 × ( 7 + 4✓3) / (7+4✓3)
=> ( 5+4✓3) ( 7+4✓3) / ( 7-4✓3)(7-4✓3)
=> 5(7 + 4✓3) +4✓3 ( 7+4✓3) / (7)² -(4✓3)²
=> 35 + 20✓3 + 28✓3 + 48 / 49-48
=> (35 + 48) + (20✓3 + 28✓3) /1
=> 83 + 48✓3
★ HOPE IT WILL HELP YOU ★
5 + 4✓3 / 7 - 4✓3
=> 5 + 4✓3 / 7 -4✓3 × ( 7 + 4✓3) / (7+4✓3)
=> ( 5+4✓3) ( 7+4✓3) / ( 7-4✓3)(7-4✓3)
=> 5(7 + 4✓3) +4✓3 ( 7+4✓3) / (7)² -(4✓3)²
=> 35 + 20✓3 + 28✓3 + 48 / 49-48
=> (35 + 48) + (20✓3 + 28✓3) /1
=> 83 + 48✓3
★ HOPE IT WILL HELP YOU ★
Answered by
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I hope this must be the answer
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