in an isosceles triangle the base angles are equal.the vertex angle is twice either base angle.what are the angles of the triangle
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let the two base angles be X
then the vertex angle will be 2X
sum of all 3 angles in a triangle is 180°
X+X+2X = 180°
solving the eq
X=45°
then vertex angle is 90°
hence the three angles are 45°,45°,90°
then the vertex angle will be 2X
sum of all 3 angles in a triangle is 180°
X+X+2X = 180°
solving the eq
X=45°
then vertex angle is 90°
hence the three angles are 45°,45°,90°
Answered by
1
Let one base angle be x then
Vertex angle = 2x
In the triangle sum of all angles = 180°
So, x + x + 2x = 180°
4x = 180°
x = 45°
2x = 90°
Hence angles of the triangle are45° , 45° & 90°.
Vertex angle = 2x
In the triangle sum of all angles = 180°
So, x + x + 2x = 180°
4x = 180°
x = 45°
2x = 90°
Hence angles of the triangle are45° , 45° & 90°.
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