Math, asked by madhugedala20, 9 months ago

rationalise the denominator√6/√3-√2​

Answers

Answered by GulzarShah
0

Answer:

√6 /√3-√2= √6 /√3-√2×√3+√2/√3+√2

= √6 ×(√3+√2)/√3²—√2²

= √18 + √12/ 3-2

= 3( √6 ± √4) /1

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Answered by 2ndiidoofTHOR940
3

Answer:

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