Rationalise the denominator
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\frac{3 - 2 \sqrt{2} }{3 + 2 \sqrt{2} }
= \frac{3 - 2 \sqrt{2} }{3 + 2 \sqrt{2} } \times \frac{3 - 2\sqrt{2} }{3 - 2 \sqrt{2} }
= \frac{ {(3 - 2 \sqrt{2} ) }^{2} }{ ({3})^{2} + ( {2 \sqrt{2}) }^{2} }
= \frac{9 - 12 \sqrt{2} + 8 }{9 + 8}
= \frac{17 - 12 \sqrt{2} }{17}
Hope \: my \: ans.s \: is \: satisfactory(^-^)
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