Math, asked by tamannaramola1125, 11 months ago

Rationalise the denominator
(I) 3/√5
ii) 1/√3-√2​

Answers

Answered by getsparkling
1

Step-by-step explanation:

i)

3 \div  \sqrt{5}

(3/root 5)× (root5 / root 5)

= 3root5 / (root 5)^2

=3 root 5 / 5

3 \sqrt{5}  \div 5

ii)

1 \div  \sqrt{3}  -  \sqrt{2}

(1 \div  \sqrt{3}  -  \sqrt{2} ) \div ( (\sqrt{3}  \ + \sqrt{2} ) \div  \sqrt{3}  +  \sqrt{2} ))

((root 3 + root 2)/( 3- 2))

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