Question

Rationalise the denominator:- (i)4/√11-√7

Answer 1

Heya !!

4 / √11–√7

=> 4 / (√11–√7) × (√11+√7) / (√11+√7)

=> [4(√11–√7)] / (11–7)

=> (4√11–4√7) / 4

=> (√11 – √7) / 4

Answer 2

HEYA !!

Here is your answer...⬇⬇

➡ Solution :-

$= \frac{4}{ \sqrt{11} - \sqrt{7} } \\ \\ to \: \: rationalizing \: \: the \: \: denominator \: \: multiply \: \: the \: \: numerator \: \: and \: \: denominator \: \: with \: \: \sqrt{11} + \sqrt{7} \\ \\ = \frac{4}{ \sqrt{11} - \sqrt{7} } \times \frac{ \sqrt{11} + \sqrt{7} }{ \sqrt{11} + \sqrt{7} } \\ \\ = \frac{4( \sqrt{11} + \sqrt{7} ) }{11 - 7} \\ \\ = \frac{4( \sqrt{11} + \sqrt{7}) }{4} \\ \\ = \frac{ \sqrt{11} + \sqrt{7} }{1} \\ \\ = \sqrt{11} + \sqrt{7}$
HOPE IT HELPS YOU..

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