Question

Rationalise the denominator in each of the following: 3+2√2/3+2√2​

Answer 1

$\huge{Answer:}$

$\\ = \frac{ 3+2√2 }{3+2√2} \times \frac{3 - 2√2}{3 - 2√2}$

$\\ { = \frac{(3)²-(2√2)²}{(3)²-(2√2)²}} = \frac{9 -8 }{9 - 8} = \frac{1}{1} = 1$

$\bold{This \: is \: the \: correct \: answer. }$