Math, asked by hima456bindu, 9 months ago

rationalise the denominator of
1 / 2+√3​

Answers

Answered by ishwarsinghdhaliwal
4

 \frac{1}{2 +  \sqrt{3} }   \\ =  \frac{1}{2 +  \sqrt{3} }   \times \frac{2 -  \sqrt{3} }{2 -  \sqrt{3} }   \\   = \frac{2 -  \sqrt{3} }{ {2}^{2} - (\sqrt {3} ) ^{2}  }   \\ =   \frac{2 -  \sqrt{3} }{4 - 3}  \\  = 2 -  \sqrt{3}

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