Question

rationalise the denominator of 1/2+
$\sqrt{3}$


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Answer 1

Step-by-step explanation:

$\implies\frac{1}{2+\sqrt{3} } \\\\ \text{rationalising factor = }2-\sqrt{3} \\\\ => \frac{1}{2+\sqrt{3} } (\frac{2-\sqrt{3}}{2-\sqrt{3} } ) \\\\ => \frac{2-\sqrt{3}}{(2+\sqrt{3} )(2-\sqrt{3})} \\\\=>\frac{2-\sqrt{3}}{2^2-\sqrt{3}^2} \\\\ => \frac{2-\sqrt{3}}{4-3} \\\\=>\frac{2-\sqrt{3}}{1}\\\\=>2-\sqrt{3} \\\\ ---------------------- \\ \underline{FORMULA \ USED} \ : \\ \\(a-b)(a+b)=a^2-b^2$