Question

Rationalise the denominator of
1/(7+3√2)​

Answer 1

Step-by-step explanation:

hope this ans helps u...

Answer 2

Answer:

$\frac{1}{7 + 3 \sqrt{2} }$

$= \frac{1}{7 + 3 \sqrt{2} } \times \frac{7 - 3 \sqrt{2} }{7 - 3 \sqrt{2} }$

$= \frac{7 - 3 \sqrt{2} }{ {(7)}^{2} - ({3 \sqrt{2}) }^{2} }$ [a²-b² = (a+b)(a-b)]

$= \frac{7 - 3 \sqrt{2} }{49 - 18}$

$= \frac{7 - 3 \sqrt{2} }{31}$