Math, asked by kollipara7363, 9 months ago

Rationalise the denominator of 1/ 7+4√3

Answers

Answered by mysticd
13

 \frac{1}{(7+4\sqrt{3})}\\= \frac{(7-4\sqrt{3})}{(7+4\sqrt{3})(7-4\sqrt{3})}\\ = \frac{(7-4\sqrt{3})}{7^{2}-(4\sqrt{3})^{2}}\\ = \frac{(7-4\sqrt{3})}{49- 48}\\ = 7 - 4\sqrt{3}

Therefore.,

\red{ \frac{1}{(7+4\sqrt{3})}}\green{ =7 - 4\sqrt{3}}

•••♪

Answered by Anonymous
8

Answer:-

 =  \frac{1}{7 + 4 \sqrt{3} }  \\  \\ rationalising \:  \: the \:  \: denominator..... \\  \\  =  \frac{1}{7 + 4 \sqrt{3} }  \times  \frac{7 - 4 \sqrt{3} }{7 - 4 \sqrt{3} }  \\  \\  =  \frac{7 - 4 \sqrt{3} }{ {(7)}^{2} -  {(4 \sqrt{3} })^{2}  }  \\  \\  =  \frac{7 - 4 \sqrt{3} }{49 - 48}  \\  \\  = 7 + - 4 \sqrt{3} ...

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