Math, asked by mohammadsaddam5945, 1 year ago

Rationalise the denominator of:

1/root 6+root 5 -root 11

Answers

Answered by Strangercitizen1525
55
1/root 6 + root 5 - root 11 * 1/(root 6 + root 5) + root 11
root 6 + root 5 + root 11 / (root 6 + root 5)^2 - (root 11)^2
root 6 + root 5 + root 11 / 6+5+2 root 30 - 11
root 6 + root 5 + root 11 / 2 root 30
root 180 + root 150 + root 330 / 60  -----------------> ans

hope it helps
Answered by Manojj
53

 \frac{1}{ \sqrt{6  +  \sqrt{5} } }   -  \sqrt{11}
 =  \frac{1}{ \sqrt{6 }  +  \sqrt{5} }   \times  \frac{ \sqrt{6}  -  \sqrt{5}  }{ \sqrt{6}   -  \sqrt{5} }  -  \sqrt{11}
 =   \frac{ \sqrt{6} -  \sqrt{5}  }{( \sqrt{6} ) {}^{2}  - ( \sqrt{5})   {}^{2} }  -  \sqrt{11}
  = \frac{ \sqrt{6}  -  \sqrt{5} }{ 6 - 5}  -  \sqrt{11}
 =  \frac{ \sqrt{6}  -  \sqrt{5} }{1}  -  \sqrt{11}
 \sqrt{6}  -  \sqrt{5}  -  \sqrt{11}

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