Question

rationalise the denominator of 1 upon 3 + root 2

Answer 1

Heya!

Here is yr answer.......

=> 1/3+√2

On rationalising......


=> 1/3+√2 × 3-√2/3-√2

=> 3-√2/9-2

=> 3-√2/7


Hope it hlpz...

Answer 2

Answer:

After rationalizing we get $\implies\frac{3}{7}-\frac{\sqrt{3}}{7}$

Step-by-step explanation:

Given: $\frac{1}{3+\sqrt{2}}$

we have to rationalize the denominator of given expression.

Consider,

$\frac{1}{3+\sqrt{2}}$

$\implies\frac{1}{3+\sqrt{2}}\times\frac{3-\sqrt{2}}{3-\sqrt{2}}$

$\implies\frac{3-\sqrt{3}}{(3)^2-(\sqrt{2})^2}$

$\implies\frac{3-\sqrt{3}}{9-2}$

$\implies\frac{3-\sqrt{3}}{7}$

$\implies\frac{3}{7}-\frac{\sqrt{3}}{7}$

Therefore, After rationalizing we get $\implies\frac{3}{7}-\frac{\sqrt{3}}{7}$