Question

Rationalise the denominator of
1 upon2 underroot 3​

Answer 1

Answer:

Rationalising

Step-by-step explanation:

1 = 1 × 2√3

2√3 2√3 2√3

= 1×2√3

2√3×2√3

= 2√3

12

= √3

6

Answer 2

Answer:

$\sqrt[2]{3} \div 12$

Step-by-step explanation:

multiple the denominator as

$\frac{1}{2 \sqrt{3} } \times \frac{2 \sqrt{3} }{2 \sqrt{3} }$

now solve it as

$\frac{1 \times 2 \sqrt{3} }{ 2 \sqrt{3} \times 2 \sqrt{3} }$

so,

you will get

$\frac{2 \sqrt{3} }{12}$

or

$\frac{ \sqrt{3} }{6}$