rationalise the denominator of 2/√3-√5
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=2/(√3-√5)
=2(√3+√5)/(√3-√5)(√3+√5)
=2(√3+√5)/(3-5)
=2(√3+√5)/-2
= -(√3+√5)
=2(√3+√5)/(√3-√5)(√3+√5)
=2(√3+√5)/(3-5)
=2(√3+√5)/-2
= -(√3+√5)
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