Math, asked by mishrakc454, 10 months ago

Rationalise the denominator of 3-2√2/3+2√2​

Answers

Answered by Adlock
2

Answer:

Rationalise 3-2root2/3+2root2

Step-by-step explanation:

First,

3-2root2/3+2root2*3-2root2/3-2root2=

(3-2root2)^2/(3+2root2)(3-2root2)

9-12root2+8/9-8=

17-12root2/1=17-12root2

Answer=17-12 root2

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Answered by venkatavineela3
0

Answer:

Step-by-step explanation:

(3-2sqrt(2))/(3+2sqrt(2))

the denominator is 3+2sqrt(2) rationalising factor is 3-2sqrt(2)

(3-2sqrt(2))(3-2sqrt(2))/(9-8)

=(3-2sqrt(2))^2/1

=9+8-12sqrt(2)

=17-12sqrt(2)

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