Question

Rationalise the denominator of 3/4-root over 7

Answer 1

$= = > \: \: \frac{3}{4 - \sqrt{7} } \\ \\ = = > \: \: \frac{3}{4 - \sqrt{7} } \times \frac{4 + \sqrt{7} }{4 + \sqrt{7} } \\ \\ = = > \: \: \frac{3(4 + \sqrt{7}) }{16 - 7} \\ \\ = = > \: \: \frac{ \cancel{3}(4 + \sqrt{7} )}{ \cancel{9}} \\ \\ = = > \: \: \frac{4 + \sqrt{7} }{3}$