Question

rationalise the denominator of 3√5-√7÷3√3+√2​

Answer 1

Answer:

Given (3√5-√7)/(3√3 + √2)

=[(3√5-√7)(3√3-√2)]/[(3√3+√2)(3√3-√2)]

=[9√15-3√10-3√21+√14]/[(3√3)²-(√2)²]

[ Since x²-y² =(x+y)(x-y)]

=[9√15-3√10-3√21+√14]/(27-2)

= (9√15-3√10-3√21+√14)/25

Answer 2

Step-by-step explanation:

$\frac{3 \sqrt{5} - \sqrt{7} }{3 \sqrt{3 + \sqrt{2} } }$

$\frac{3 \sqrt{5 - \sqrt{7} } }{3 \sqrt{3 } + \sqrt{2} } \times \frac{3 \sqrt{3} - \sqrt{2} }{3 \sqrt{3 - \sqrt{2} } }$

just solve this u get urs answer perfectly