Question

rationalise the denominator of 3root2/root8+root5​

Answer 1

Step-by-step explanation:

$\frac{3 \sqrt{2} }{ \sqrt{8} + \sqrt{5} } \times \frac{ \sqrt{8} - \sqrt{5} }{ \sqrt{8} - \sqrt{5} } \\ = \frac{12 - 3 \sqrt{10} }{(\sqrt{8}) ^{2} - ( \sqrt{5})^{2} } \\ = \frac{3(4 - \sqrt{10}) }{8 - 5} \\ = \frac{3(4 - \sqrt{10} )}{3} \\ = 4 - \sqrt{10}$