rationalise the denominator of 5√3-4√2÷4√3+3√2
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Couldn't write it sorry
I just tried it maybe the answer is wrong
So i recommend u check it first. :)
I just tried it maybe the answer is wrong
So i recommend u check it first. :)
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aadeshyadav7:
np
Answered by
42
Hiii friend,
5✓3-4✓2/4✓3+3✓2
Rationalizing the denominator 4✓3+3✓2
=>. 5✓3-4✓2/4✓3+3✓2 × 4✓3-3✓2/4✓3-3✓2
we know that,
(A+B)(A-B) = A²-B²
So,
=> (5✓3-4✓2)(4✓3-3✓2)/(4✓3+3✓2)(4✓3-3✓2)
=> 5✓3(4✓3-3✓2)-4✓2(4✓3-3✓2)/(4✓3)² - (3✓2)²
=> 20 × 3 - 15✓6 - 16✓6 + 12 × 2 / 48 - 18
=> 60 - 31✓6 + 24/30
=> 84-31✓6/30
HOPE IT WILL HELP YOU..... :-)
5✓3-4✓2/4✓3+3✓2
Rationalizing the denominator 4✓3+3✓2
=>. 5✓3-4✓2/4✓3+3✓2 × 4✓3-3✓2/4✓3-3✓2
we know that,
(A+B)(A-B) = A²-B²
So,
=> (5✓3-4✓2)(4✓3-3✓2)/(4✓3+3✓2)(4✓3-3✓2)
=> 5✓3(4✓3-3✓2)-4✓2(4✓3-3✓2)/(4✓3)² - (3✓2)²
=> 20 × 3 - 15✓6 - 16✓6 + 12 × 2 / 48 - 18
=> 60 - 31✓6 + 24/30
=> 84-31✓6/30
HOPE IT WILL HELP YOU..... :-)
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