Math, asked by ahirwarr3517, 10 months ago

Rationalise the denominator of 5/root 15 - 2 root2.

Answers

Answered by ankushsaini23
0

Answer:

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According to question:-

 \frac{5}{ \sqrt{15} -  \sqrt[2]{2}  }

 \frac{5}{ \sqrt{15} -  \sqrt[2]{2}  }  \times  \frac{ \sqrt{15} +  \sqrt[2]{2}  }{ \sqrt{15} +  \sqrt[2]{2}  }

 =  \frac{5( \sqrt{15} +  \sqrt[2]{2})  }{( { \sqrt{15} })^{2} - ( { \sqrt[2]{2} })^{2}  }

 =  \frac{ \sqrt[5]{15} +  \sqrt[10]{2}  }{15 - 8}

 =  \frac{ \sqrt[5]{15} +  \sqrt[10]{2}  }{7}

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