rationalise the denominator of 5/root 3-root5
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1
=5/√3-√5×√3+√5/√3+√5
=5√3+5√5/-2
=5√3+5√5/-2
Answered by
14
First of all,
What is 'Rationalisation'?
Rationalisation : It is a process to change the irrational number into a rational number by multipling with some suitable irrational numbers.
The factor which multipling to the given irrational number to change as irrational is called a "Rationalisation factor".
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Q. Rationalise the denominator of 5/(√3 - √5)
Solution :
5/(√3 - √5) × (√3 + √5)/(√3 + √5)
= [ 5×(√3 + √5) ] / [ (√3)² - (√5)² ]
= 5 × [ √3 + √5 / ( 3 - 5 ) ]
= 5 × [ √3 + √5 / ( -2 ) ]
= -5/2 ( √3 + √5 )
What is 'Rationalisation'?
Rationalisation : It is a process to change the irrational number into a rational number by multipling with some suitable irrational numbers.
The factor which multipling to the given irrational number to change as irrational is called a "Rationalisation factor".
================================
Q. Rationalise the denominator of 5/(√3 - √5)
Solution :
5/(√3 - √5) × (√3 + √5)/(√3 + √5)
= [ 5×(√3 + √5) ] / [ (√3)² - (√5)² ]
= 5 × [ √3 + √5 / ( 3 - 5 ) ]
= 5 × [ √3 + √5 / ( -2 ) ]
= -5/2 ( √3 + √5 )
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