verify the relationship between the zeros and the coefficients of the polynomial x^2+7x+10
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P(x)=x^2 +7x+ 10
p(x)=x^2+5x+2x+10
p(x)=x(x+5) + 2(x+5)
p(x)=(x+5)(x+2)
x=-5,x=-2.
Let alpha = -5 and beta = -2.
Sum of zeroes= -5+(-2)=-7.
Product of zeroes= -5 x -2 =10.
a=1,b=7,c=10.
-b/a=-7.
c/a=10.
Hence we can say that,
Sum of zeroes = -b/a=-7.
Product of zeroes = c/a =10.
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p(x)=x^2+5x+2x+10
p(x)=x(x+5) + 2(x+5)
p(x)=(x+5)(x+2)
x=-5,x=-2.
Let alpha = -5 and beta = -2.
Sum of zeroes= -5+(-2)=-7.
Product of zeroes= -5 x -2 =10.
a=1,b=7,c=10.
-b/a=-7.
c/a=10.
Hence we can say that,
Sum of zeroes = -b/a=-7.
Product of zeroes = c/a =10.
HOPE IT HELPS U...
PLEASE MARK IT AS BRAINLIEST...
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