Question

rationalise the denominator of √6/√3-√2

Answer 1

multiply numerator and denominator by (√3+√2)


[√6(√3+√2)]/(√3-√2)(√3+√2)

=> (√18+√12)/(√3)²-(√2)²
( a+b)(a-b) => a²-b²

=> (√18+√12)/3-2
=> √18+√12



hope this helps

Answer 2

Hey
here's your answer !!

√6 / ( √3-√2 )
= √6 ( √3 + √2 ) / ( √3-√2 )( √3 + √2 )
= ( √6 * √3 ) + ( √6 * √2 ) / ( √3 )² - ( √2 )²
= √18 + √12 / ( 3 -2 )
= 3√2 +2√3 ( ANSWER )

hope it helps !!