Math, asked by maniparanth, 10 months ago

Rationalise the denominator of 7√3÷√10+√3-2√5÷√6+√5-3√2÷3√2+√15

Answers

Answered by geetalibora19
2

Answer:

 =  \sqrt{30}  - 3 - (2 \sqrt{30}  - 16) - 6 -  \sqrt{30} )

 =  \sqrt{30}  - 3 - 2 \sqrt{30}  + 10 - 6 +  \sqrt{30}

 = 10 - 9 + 2 \sqrt{30}  - 2 \sqrt{30}

 = 1

Attachments:
Answered by Ayushibora
0

Answer:

 \sqrt{30}   - 3 -  (2 \sqrt{30} - 16) - 6 -  \sqrt{30}  )

 =  \sqrt{30}  - 3 - 2 \sqrt{30} + 10 - 6 +  \sqrt{30}

 = 10 - 9 + 2 \sqrt{30}  - 2 \sqrt{30}

 = 1

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