Math, asked by marthaladhrithi, 9 months ago

rationalise the denominator of root6/root2+root3

Answers

Answered by Anonymous
19

 \frac{ \sqrt{6} }{ \sqrt{2}  +  \sqrt{3} }  \times  \frac{ \sqrt{2} -  \sqrt{3}  }{ \sqrt{2}  -  \sqrt{3} }

 \frac{ \sqrt{12} -  \sqrt{18}  }{2 - 3}

 \frac{2 \sqrt{3}  - 3 \sqrt{2} }{ - 1}

 - (2 \sqrt{3}   -  3 \sqrt{2} )

 - 2 \sqrt{3}  + 3 \sqrt{2}

please mark as branliest answer

Answered by inasingh651
14

Answer:

this is the answer for more precise answer you can just do it in calculator. hope it will help you. Pls mark it as the brainliest answer

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