Math, asked by k68159244, 1 month ago


Rationalise the denominator of
2 \div  \sqrt{7}  +  \sqrt{5}

Answers

Answered by Evilhalt
241

{  \textsf{ \textbf{ \large{ \sf{ \color{red}{➣ \:  Question : }}}}}}

  • Rationalise the denominator of :–

 \implies \sf  \large{ \frac{2}{ \sqrt{7} +  \sqrt{5}  } }

{  \textsf{ \textbf{ \large{ \sf{ \color{red}{➣ \: Answer :  }}}}}}

\circ \:  \: { \underline{ \boxed{ \color{violet}{( \sqrt{7}  -  \sqrt{5} }}}}

{  \textsf{ \textbf{ \large{ \sf{ \color{red}{➣ \: Solutíon:  }}}}}}

 \sf  \underline{to \: rationalise\: } \implies \sf  \large{ \frac{2}{ \sqrt{7} +  \sqrt{5}  } }

  • By rationalising the denominator

 \implies \sf  \large{ \frac{2}{ \sqrt{7} +  \sqrt{5}  }  \times  \frac{\sqrt{7}  -   \sqrt{5}}{\sqrt{7}  -   \sqrt{5}} }

  • using the formula a²- b² = (a - b) (a + b)

 \implies \sf  \large{ \frac{2( \sqrt{7} -  \sqrt{5}  )}{ { \sqrt{7} \:  }^{2} -  { \sqrt{5} \:  }^{2}  }  }

 \implies \sf  \large{ \frac{2( \sqrt{7} -  \sqrt{5} ) }{(7 - 5)}}

 \implies \sf  \large{ \frac{2( \sqrt{7} -  \sqrt{5} ) }{(2)}}

 \implies \sf  \large \cancel{ \frac{2( \sqrt{7} -  \sqrt{5} ) }{(2)}}

 \implies { \underline{ \boxed{ \color{green}{( \sqrt{7}  -  \sqrt{5} }}}}

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Answered by muskansingh3707126
4

Step-by-step explanation:

{  \textsf{ \textbf{ \large{ \sf{ \color{red}{➣ \:  Question : }}}}}}

Rationalise the denominator of :–

 \implies \sf  \large{ \frac{2}{ \sqrt{7} +  \sqrt{5}  } }

{  \textsf{ \textbf{ \large{ \sf{ \color{red}{➣ \: Answer :  }}}}}}

\circ \:  \: { \underline{ \boxed{ \color{violet}{( \sqrt{7}  -  \sqrt{5} }}}}

{  \textsf{ \textbf{ \large{ \sf{ \color{red}{➣ \: Solutíon:  }}}}}}

 \sf  \underline{to \: rationalise\: } \implies \sf  \large{ \frac{2}{ \sqrt{7} +  \sqrt{5}  } }

By rationalising the denominator

 \implies \sf  \large{ \frac{2}{ \sqrt{7} +  \sqrt{5}  }  \times  \frac{\sqrt{7}  -   \sqrt{5}}{\sqrt{7}  -   \sqrt{5}} }

using the formula a²- b² = (a - b) (a + b)

 \implies \sf  \large{ \frac{2( \sqrt{7} -  \sqrt{5}  )}{ { \sqrt{7} \:  }^{2} -  { \sqrt{5} \:  }^{2}  }  }

 \implies \sf  \large{ \frac{2( \sqrt{7} -  \sqrt{5} ) }{(7 - 5)}}

 \implies \sf  \large{ \frac{2( \sqrt{7} -  \sqrt{5} ) }{(2)}}

 \implies \sf  \large \cancel{ \frac{2( \sqrt{7} -  \sqrt{5} ) }{(2)}}

 \implies { \underline{ \boxed{ \color{green}{( \sqrt{7}  -  \sqrt{5} }}}}

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