rationalise the denominator of the following 1 by root 7 minus root 6
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Answered by
5
Answer:
1÷√7-√6×√7+√6÷√7×√6
√7+√6 ÷√7^2-√6^2 ((a+b)(a-b)=a^2-b^2)
Step-by-step explanation:
√7+√6÷7-6
√7+√6÷1
=√7+√6
Hope it helps
Answered by
8
1 / √7 - √6
:. 1 / ( √7 - √6 ) * √7 + √6 / √7 + √6
:. √7 + √6 / ( √7 - √6 ) ( √7 + √6 )
:. √7 + √6 / (√7) square - (√6) square
:. √7 + √6 / 7 - 6
:. √7 + √6 / 1
:. √7 + √6
HOPE u r satisfied .
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