Question

rationalise the denominator of the following 6 by root 5 + root 2​

Answer 1

Answer:

hiii

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Step-by-step explanation:

6/√5+√2

6/√5+√2×√5-√2/√5-√2

6(√5-√2)/5-2...(a+b)(a-b)=a^2-b^2

6(√5-√2)/3

2(√5-√2).

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Answer 2

Step-by-step explanation:

Given that

6 / √5 + √2

Multiply and divide with √5 - √2 on either sides .

6 / √5 + √2 × √5 - √2 / √5 - √2

We know that

( a + b ) × ( a - b ) = a2 - b2

6 × ( √5 - √2 ) / ( √5 ) 2 - ( √2 ) 2

6 × ( √5 - √2 ) / 5 - 2

6 × ( √5 - √2 ) / 3

2 ( √5 - √2 )